question_answer 48)

Show that tangent to the curve y = 7x3 + 11 at the points where x = 2 and x = –2 are parallel. 

Answer:

Given curve is             y = 7x3 + 11                              ?. (1)             m1 = slope of tangent to (1) at x             m2 = slope of tangent to (1) at x                   Since m1 = m2       Therefore tangents to (1) at x = 2 and x = ?2 are parallel.