Answer:
Let
(x × y × 2) be the tank
V
= Volume of tank
=
8m3 (given)
Area
of base of tank (A1) = xy
(A2)
Area of 4 walls
=
2(l + b) × h
=
2(x + y) × 2
=
4 (x + y)
of building
C
= 70A1 + 45 A2 = 70 xy + 45
×
4 (x + y)
[Using
(1)]
?.
(2)
(x
> 0)
Now
is minimum
when x = 2
Minimum
cost of building
=
280 + 180 × 4 = 280 + 720
=
Rs.1000.
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