Answer:
Let
x and y be the required numbers such that
x
+ y = 16
and
sum of their cubes
S
= x3 + y3 = x3 + (16 ? x)3 (Using
(1))
= 6x + 3 ×
2 (16 ? x)
=
6(x + 16 ? x) = 96
is
minimum when x = 8
Required
numbers are 8, 8.
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