Answer:
Given
x + y = 35 ?. (1)
Let
P = x2y5 = (35 ? y)2 y5
6125y4
+ 7y6 ? 420y5 = 0
5y4
(875 + y2 ? 60y) = 0
y2
? 60y + 875 = 0
(y ? 25)
(y ? 35) = 0
y = 25
and as by
(1),
x
+ y = 35 and x > 0.
=
7y3 [3500 + 6y2 ? 3000]
is maximum
when y = 25 (1)
Required
numbers are 10 and 25.
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