Answer:
f(x) = 3x4 ?
8x3 + 12x2 ? 48x + 25
= 12 [x3
? 2x2 + 2x ? 4]
= 12 [x2
(x ? 2) + 2(x ? 2)]
= 12 (x ? 2) (x2
+ 2)
f?(x) = 0
Maximum
value of f(x) = 25 at x = 0 and minimum value of (x) = ?39 at x = 2.
x
0
2
3
f(x)
25
-39
16
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