Answer:
(I) f(x) = |x +
2| ? 1
f(x) = ?1
and
Max. f(x) does not
exist.
(II) g(x) = ?|x
+ 1| + 3
= 3 ? |x +
1|
Max. g(x)
= 3 and
Min. g(x) does not
exist.
III. h(x) = sin (2x) +
5
Since ?1
Min . f(x)
= 6
Max. h (x = 6
IV. f(x) = |sin (4x) +
3|
Since ? 1
f(x) = 2
sin Max. f(x) = 4
V. h(x) = x + 1,
Since ? 1 < x
< 1
0 < x +
1 < 2
0 < h
(x) < 2
Therefore for
h(2), min. and max. values of do not exist.
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