question_answer 1)

Find the area enclosed by the parabola 4y = 3x2 and the line 2y = 3x + 12. 

Answer:

Given curve is 4y = 3x2                                           ?? (1)             and 2y = 3x + 12             (1)   and (2) x2 = 2x + 8 x2 ? 2x ? 8 = 0 (x ? 4) (x + 2) = 0 x = 4, ? 2 (2)  y = 12 when x = 4       and y = 3 when x = ?2    points of intersection are (4, 12) and (?2, 3) Required area = Shaded area                                           = 36 ? 16 + 9 ? 2 = 27.