Answer:
Let
R1 = {(x, y) : y2 4x}
R2
= {(x, y) : 4x2 + 4y2 9}
required
region R =
For
R1, consider y2 = 4x ? (1)
Put
(1, 0) in y2 which is
true
is the
inside area of the parabola.
For
R2, consider 4x2 + 4y2 = 9 ...
(2)
(2)
represents a circle with centre (0, 0) and r
Put
(1, 0) in 4x2 + 4y2
is the
inside area of the circle.
Shaded
area
Now
(1) & (2)
4x2
+ 16x ? 9 = 0
4x2
+ 16x ? 9 = 0
2x (2x
+ 9) ? 1 (2x + 9) = 0
(2x +
9) ? 1 (2x + 9) = 0
(2x +
9) (2x ? 1) = 0
[By
(1)]
Points
of intersection are and
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