Answer:
Energy to be expend
to burn 5 kg fat
\[=5\times
7000\times {{10}^{3}}\text{ cal}\]
\[=35\times
{{10}^{6}}\times 4.2\text{ }J\text{ }=\text{ }147\times {{10}^{6}}J\]
Let
lie completes N up and down to expend this energy
\[\therefore
\] Total energy to be expend in N up and down motions = nigh \[\times \] N
\[=60\times
10(10+5)N\]
\[=60\times
10\times 15\text{ }N=(900\,N)J\]
\[\therefore
\] \[900\text{ }N=147\times {{10}^{6}}\]
or \[N=\,\frac{147\times
\,{{10}^{6}}}{900}\,=\,16.3\,\,\times \,{{10}^{4}}\]
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