• question_answer 58)   The value of${{\Delta }_{f}}{{H}^{{}^\circ }}$for $N{{H}_{3}}$ is$-9.18kJmo{{l}^{-1}}$. Calculate enthalpy change for the following reaction: $2N{{H}_{3}}(g)\to {{N}_{2}}(g)+3{{H}_{2}}(g)$

Answer:

The given reaction: $2N{{H}_{3}}(g)\to {{N}_{2}}(g)+2{{H}_{2}}(g)$ ${{\Delta }_{r}}{{H}^{{}^\circ }}=[{{\Delta }_{f}}H_{{{N}_{2}}}^{{}^\circ }+3{{\Delta }_{f}}H_{{{H}_{2}}}^{{}^\circ }]-[2{{\Delta }_{f}}H_{N{{H}_{3}}}^{{}^\circ }]$$=0+3\times 0-2\times (-91.8)$ $=+183.6kJ$

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