11th Class Chemistry Thermodynamics

  • question_answer 33) The equilibrium constant for a reaction is 10. What will be the value of \[\Delta {{G}^{{}^\circ }}?R=8.314J{{K}^{-1}}mo{{l}^{-1}},T=300K.\]  

    Answer:

    \[\Delta {{G}^{{}^\circ }}=-2.303RT\log K\] \[=-2.303\times 8.314\times 300\times \log 10=-5744.1J\]  


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