• question_answer 33) The equilibrium constant for a reaction is 10. What will be the value of $\Delta {{G}^{{}^\circ }}?R=8.314J{{K}^{-1}}mo{{l}^{-1}},T=300K.$

$\Delta {{G}^{{}^\circ }}=-2.303RT\log K$ $=-2.303\times 8.314\times 300\times \log 10=-5744.1J$