• question_answer 22) Calculate the number of kJ of heat necessary to raise the temperature of 60 g of aluminium from$35{}^\circ C$to$55{}^\circ C$. Molar heat capacity of Al is$24Jmo{{l}^{-1}}{{K}^{-1}}$.

Information shadow: Heat capacity 'C of $Al=24Jmo{{l}^{-1}}{{K}^{-1}}$ Temperature rise, $\Delta T=20$ Mass of aluminium = 60 g Number of moles of $Al=\frac{60}{27}=2.22$ Problem solving strategy: Heat absorbed to raise the temperature of n mole $\text{ }\!\!'\!\!\text{ Al }\!\!'\!\!\text{ }$ by $\Delta T$may be calculated as, $q=nC\Delta T$ Working it out: $q=2.22\times 24\times 20=1065.6J$ = 1.065 kJ