• # question_answer 20) In a process, 701 J of heat is absorbed by a system and 394J of work is done by the system. What is the change in internal energy for the process?

$q\text{ }=+\text{ }701\text{ }J$(Heat absorbed) $w=-394\text{ }J$ (Work done by the system) $\Delta U=q-w=701-394$ $=307J$ i.e., Internal energy of system will increase by 307 J.