Column I | Column II |
(i) \[BF_{4}^{-}\] | (a) Oxidation state of central atom is +4 |
(ii) \[AlC{{l}_{3}}\] | (b) Strong oxidising agent |
(iii) \[SnO\] | (c) Lewis acid |
(iv) \[Pb{{O}_{2}}\] | (d) Can be further oxidised |
(e) Tetrahedral shape |
Answer:
(i-e) (ii-c) (iii-d) (iv-a, b).
[
\[BF_{4}^{-}\]
\[s{{p}^{3}}\]-hybridisation
Tetrahedral shape
\[AlC{{l}_{3}}\]
Electron deficient
Lewis acid
\[SnO\]
\[+4\]state is more stable than +2
Can be further oxidised
\[Pb{{O}_{2}}\]
\[x-4=0,x=4,\]i.e., oxid, state 4
However, in lead +2 oxidation state is more stable than +4 state
acts as strong oxidising agent
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