Answer:
Boric acid does not behave as a
protonic acid but behaves as a Lewis acid, i.e., it accepts a pair of electrons
from \[O{{H}^{-}}\] ion of the water molecule in aqueous solution.
\[H-OH+B{{(OH)}_{3}}\xrightarrow{{}}{{[B{{(OH)}_{4}}]}^{-}}+{{H}^{+}}\]
[For more details see the answer
of question 6.]
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