question_answer 1)

  Complete the following chemical equations : \[Z+3LiAl{{H}_{4}}\to X+3LiF+3Al{{F}_{3}}\] \[X+6{{H}_{2}}O\to Y+6{{H}_{2}}\] \[3X+3{{O}_{2}}\to {{B}_{2}}{{O}_{3}}+3{{H}_{2}}O\]

Answer:

  Z is \[B{{F}_{3}}\] and X is\[{{B}_{2}}{{H}_{6}}\]. \[\underset{(Z)}{\mathop{4B{{F}_{3}}}}\,++3Lil{{H}_{4}}\xrightarrow{{}}\underset{(X)}{\mathop{2{{B}_{2}}{{H}_{6}}}}\,+3LiCl+3AlC{{l}_{3}}\] Diborane \[({{B}_{2}}{{H}_{6}})\] reacts readily with water liberating hydrogen. \[\underset{(X)}{\mathop{{{B}_{2}}{{H}_{6}}}}\,+6{{H}_{2}}O\xrightarrow{{}}\underset{(Y)}{\mathop{2{{H}_{3}}B{{O}_{3}}}}\,+6{{H}_{2}}\] \[\underset{(X)}{\mathop{{{B}_{2}}{{H}_{6}}}}\,+3{{O}_{2}}\xrightarrow{{}}{{B}_{2}}{{O}_{3}}+3{{H}_{2}}O\] The reaction is highly exothermic.