Answer:
\[\mathbf{BC}{{\mathbf{l}}_{\mathbf{3}}}\]is
an electron deficient compound as the boron atom acquires six electrons in its
outermost shell. It can accept a pair of electrons from a suitable donor to
attain an octet configuration. Thus, \[BC{{l}_{3}}\] acts as a Lewis acid.
\[AlC{{l}_{3}}\]is also an
electron deficient compound and accepts alone pair from a donor and acts as a
Lewis acid.
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