Answer:
(a) \[{{P}_{15}}\to
1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}}\mathbf{3p}_{\mathbf{x}}^{\mathbf{1}}\mathbf{3p}_{\mathbf{y}}^{\mathbf{1}}\mathbf{3p}_{\mathbf{z}}^{\mathbf{1}}\]
(3
unpaired electrons in 3p)
(b) \[S{{i}_{14}}\to
1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}},\mathbf{3p}_{\mathbf{x}}^{\mathbf{1}}\mathbf{3p}_{\mathbf{y}}^{\mathbf{1}}\]
(2 unpaired electrons in 3p)
(c) \[C{{r}_{24}}\to
1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}\mathbf{3}{{\mathbf{d}}^{\mathbf{6}}},4{{s}^{2}}\]
(6 unpaired
electrons in 3d and 4s)
(d) \[F{{e}_{26}}\to
1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}\mathbf{3}{{\mathbf{d}}^{\mathbf{6}}},4{{s}^{2}}\]
(4 unpaired electrons in 3d)
(e) \[K{{r}_{36}}\to
1{{s}^{2}},2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{10}},4{{s}^{2}}4{{p}^{6}}\]
(0 unpaired electron)
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