Answer:
Let x photons are received by the detector.
\[E=x\,h\,v\]
\[=x\,h\frac{c}{\lambda
}\]
\[3.15\times
{{10}^{-18}}=x\times \frac{6.626\times {{10}^{-34}}\times 3\times
{{10}^{8}}}{600\times {{10}^{-9}}}\]
\[x=9.545\approx 10\]photons
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