Answer:
\[E=x\,h\frac{c}{\lambda },x=\] = number of photons
\[=\frac{5.6\times
{{10}^{24}}\times 6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{337.1\times
{{10}^{-9}}}\]
\[=3.289\times
{{10}^{6}}\text{J}\]
You need to login to perform this action.
You will be redirected in
3 sec