question_answer 62)

An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than electrons, find the symbol of the ion.

Answer:

Let number of electrons in the ion = \[x\] w\[\therefore \] Number of neutrons = \[x+\frac{11.1x}{100}=1.111x\] Number of electrons in the neutral atom = x -1 Mass number = \[(x-1)+1.111x=37\] \[x\] = 18 Atomic number = \[x-1=17\] Symbol: \[_{17}^{37}C{{l}^{-}}\]