Answer:
Let number of protons in the element = \[x\]
Number of neutrons = \[\frac{131.7}{100}x=1.317x\]
Mass number = \[x+1.317x\]
\[81=2.317x\]
\[x=34.95=35\]
Atomic symbol will be ( \[\,_{35}^{81}Br\]).
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