question_answer 55)

\[2\times {{10}^{8}}\]atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 3 cm.

Answer:

Total no. of atoms x diameter = length \[2\times {{10}^{8}}\times d=3\] \[d=1.5\times {{10}^{-8}}cm\] \[r=\frac{1.5\times {{10}^{-8}}}{2}=0.75\times {{10}^{-8}}cm\] \[=0.075\times {{10}^{-7}}cm\] \[=0.075\times {{10}^{-9}}m=0.075nm\]