Answer:
\[\Delta E={{E}_{5}}-{{E}_{1}}\]
\[=\frac{-2.18\times {{10}^{-11}}}{{{5}^{2}}}-\left(
\frac{-218\times {{10}^{-11}}}{{{1}^{2}}} \right)\]
\[=\frac{24}{25}\times
2.18\times {{10}^{-11}}erg\]
\[=2.0928\times
{{10}^{-11}}erg=2.0928\times {{10}^{-18}}\text{J}\]
\[\Delta E=\frac{hc}{\lambda }\]
\[\lambda =\frac{hc}{\Delta
E}=\frac{6.626\times {{10}^{-27}}\times 3\times {{10}^{10}}}{2.0928\times
{{10}^{-11}}}\]
\[=9.498\times
{{10}^{-6}}cm=949.8\times {{10}^{-8}}cm\]
\[=9.498\times {{10}^{-6}}m\]
\[=949.8\overset{o}{\mathop{\text{A}}}\,\]
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