question_answer 34)

What is the maximum number of emission lines when the excited electron of H-atoms in \[n=6\] drops to the ground state?

Answer:

Number of spectral lines = \[\frac{({{n}_{2}}-{{n}_{1}})({{n}_{2}}-{{n}_{1}}+1)}{2}\] \[{{n}_{2}}=6,\,\,{{n}_{1}}=1\] \[\therefore \] Number of lines = \[\frac{(6-1)(6-1+1)}{2}=15\]