Answer:
Information shadow: Programmes of a particular
radiostation are broadcasted on a particular frequency. In the problem, the
frequency on which programmes of All India Radio, Delhi is broadcasted, is
given.
Frequency, \[v=1.368kHz\]
\[=1368\,Hz\] (i)
(1 kHz = 1000 Hz: conversion
factor used)
All electromagnetic radiations
propagate with constant speed through a medium, i.e., velocity of light.
Velocity, \[c=3\times
{{10}^{8}}m/\sec \] (ii)
Problem solving strategy:
In the given problem, wavelength of the radiation is required. It can be
calculated using the following relation:
\[\lambda =\frac{c}{v}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,......(iii)\]
Working it out:
Substituting the values of c and v in equation (iii) we get
\[\lambda
=\frac{3\times {{10}^{8}}}{1368}=2.192\times {{10}^{5}}m.\]
The radiation of wavelength \[2.192\times {{10}^{5}}m\] lies
in the radiowave region of the electromagnetic spectrum.
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