Answer:
In hydrogen atom, energy of
different orbitals depends on the principal quantum numbers only.
\[1s<2s=2p<3s=3p=3d<4s=4p=4d=4f...\]In
multielectron species, the energy of orbitals depends on both ?n' and ?f?
\[1s<2s<2p<3s<3p<4s<3d\]
Lower is the values of \[(n+l)\],
lower is the energy of orbitals.
If \[(n+l)\] values are same
then the orbital with lower value of t n' will have lesser energy.
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