Answer:
de Broglie wavelength can be
calculated as, \[\lambda =\frac{h}{m\upsilon }\] ?(i)
Given : \[m=100\text{
}g=0.1\text{ }kg\]
\[\upsilon
=100km/hr=\frac{100\times 1000}{60\times 60\sec }=\frac{1000}{36}m{{s}^{-1}}\]
\[h=6.626\times {{10}^{-34}}Js\]
\[\lambda =\frac{6.626\times
{{10}^{-34}}}{0.1\times \frac{1000}{36}}=238.5\times {{10}^{-36}}m\]
Wavelength is so small that wave
nature cannot be observed.
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