Answer:
(c) Partial pressure of
\[{{O}_{2}}={{x}_{{{O}_{2}}}}\times
p=\frac{4}{5}\times 1=0.8\,\,atm\]
\[=0.8\times
{{10}^{5}}N{{m}^{-2}}=8\times {{10}^{4}}N{{m}^{-2}}\]
You need to login to perform this action.
You will be redirected in
3 sec