question_answer 3)

At \[25{}^\circ C\]and 760 mm Hg pressure a gas occupies 600 mL volume. What will be its pressure at a height, where temperature is \[10{}^\circ C\]and the volume of the gas is 640 mL?

Answer:

Information shadow: \[{{P}_{1}}=760mm\,Hg,\,\,\,{{V}_{1}}=600mL,\,\,\,\,\,{{T}_{1}}=298K\] \[{{P}_{2}}=?,\] \[{{V}_{2}}=640mL,\,\,\,\,\,{{T}_{2}}=283K\] Pressure, temperature and volume, all are changing. Problem solving strategy: Combination of Boyle's and Charles' law is used \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] Working it out: \[\frac{760\times 600}{298}=\frac{{{P}_{2}}\times 640}{283}\] \[{{P}_{2}}=676.6mm\,Hg\]