Answer:
We know,
\[PV=\frac{w}{W}RT\]
For Gas:\[PV=\frac{2.9}{M}\times
R\times 368\,\,\,\,\,\,\,\,\,\,\,.....(i)\]
For
Hydrogen:
\[PV=\frac{0.184}{2}\times
R\times 290\,\,\,\,\,\,\,\,\,.....(ii)\]
From Eqns.
(i) and (ii),
\[\frac{2.9}{M}\times R\times 368=\frac{0.184}{2}\times R\times 290\]
\[M=\frac{2.9\times 368\times 2}{0.184\times 290}\]
\[=40g\,mo{{l}^{-1}}\]
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