question_answer 14)

The density of a gas is found to be \[5.46\text{ }g/d{{m}^{3}}\]at \[27{}^\circ C\] and under 2 bar pressure. What will be its density at STP?

Answer:

We know, \[PM=dRT\] For a gas we may use: \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{d}_{1}}{{T}_{1}}}{{{d}_{2}}{{T}_{2}}}\,\,\,\,\,\,\,\,\,\,.....(i)\] \[{{P}_{1}}=2bar,\] \[{{P}_{2}}=1.01325bar\] \[{{d}_{1}}=5.46g/d{{m}^{3}},\] \[{{d}_{2}}=?\] \[{{T}_{1}}=300K,\] \[{{T}_{2}}=273K\] Substituting these values in Eqn. (i) \[\frac{2}{1.01325}=\frac{5.46\times 300}{{{d}_{2}}\times 273}\] \[{{d}_{2}}=3.04g/d{{m}^{3}}\]