Answer:
Unit of \[\frac{P{{V}^{2}}{{T}^{2}}}{n}=\frac{Pa\times
{{({{m}^{3}})}^{2}}\times {{K}^{2}}}{mol}\]
\[=Pa\times {{m}^{6}}\times {{K}^{2}}\times mo{{l}^{-1}}\]
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