question_answer 1)

2.9 g of a gas at \[95{}^\circ C\]occupied the same volume as 0.184 g of dihydrogen at \[17{}^\circ C\]and at the same pressure. What is the molar mass of the gas?

Answer:

We know, \[PV=\frac{w}{W}RT\] For Gas:\[PV=\frac{2.9}{M}\times R\times 368\,\,\,\,\,\,\,\,\,\,\,.....(i)\] For Hydrogen: \[PV=\frac{0.184}{2}\times R\times 290\,\,\,\,\,\,\,\,\,.....(ii)\] From Eqns. (i) and (ii), \[\frac{2.9}{M}\times R\times 368=\frac{0.184}{2}\times R\times 290\] \[M=\frac{2.9\times 368\times 2}{0.184\times 290}\] \[=40g\,mo{{l}^{-1}}\]