question_answer 1)

Calculate the total pressure in a mixture of 8 g of oxygen and 4 g of dihydrogen confined in a vessel of \[1\,d{{m}^{3}}\]at\[~27{}^\circ C\]. \[(R=0.083\text{ }bar\text{ }d{{m}^{3}}{{K}^{-1}}mo{{l}^{-1}})\]

Answer:

\[PV=nRT\] \[PV=({{n}_{1}}+{{n}_{2}})RT\] \[PV=\left( \frac{{{w}_{1}}}{{{M}_{1}}}+\frac{{{w}_{2}}}{{{M}_{2}}} \right)RT\] \[P\times 1=\left( \frac{8}{32}+\frac{4}{2} \right)\times 0.083\times 300\] \[P=56.025bar\]