question_answer 1)

Calculate the temperature of 4.0 moles of a gas occupying \[5d{{m}^{3}}\] at 3.32 bar (R = 0.083 bar \[d{{m}^{3}}\,{{K}^{-1}}\,mo{{l}^{-1}}).\]

Answer:

Applying formula : \[PV=nRT\] \[P=3.32bar,V=5d{{m}^{3}},n=4moles\] \[R=0.083bar\,d{{m}^{3}}{{K}^{-1}}mo{{l}^{-1}}\] Substituting these values in Eqn. (i) \[3.32\times 5=4\times 0.083\times T\] \[T=\frac{3.32\times 5}{4\times 0.083}=50K\]