Answer:
3 mol \[NaOH\] is dissolved in
1000 g solvent.
Thus, Mass of solution \[=1000+40\times
3=1120g\]
Volume of solution
\[=\frac{Mass}{Density}=\frac{1120}{1.11}=1009mL.\]
Molarity of solution can be
calculated as:
\[M=\frac{{{w}_{B}}\times
1000}{{{m}_{B}}\times V}=\frac{120\times 1000}{40\times 1009}=2.97\]
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