• # question_answer 75)   Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc. Following reaction takes place : $Zn+2HCl\to ZnC{{l}_{2}}+{{H}_{2}}$ Calculate the volume of hydrogen gas liberated at STP, when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP; atomic mass of $Zn=65.3\,u$.

Answer:

$\underset{\underset{65.3g}{\mathop{1\,mol}}\,}{\mathop{Zn}}\,+2HCl\to ZnC{{l}_{2}}+\underset{\underset{22.7L\,at\,STP}{\mathop{1\,mol}}\,}{\mathop{{{H}_{2}}}}\,$ Volume of ${{H}_{2}}$ gas liberated by 32.65 g Zinc a $\frac{22.7}{65.3}\times 32.65$ $=11.35L$at STP

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