Answer:
Molecular mass of \[NaOH=23+16+1=40\]
No. of moles of \[NaOH=\frac{4}{40}=\frac{1}{10}\]
Volume of
solution = \[200c{{m}^{3}}=0.2L\]
Molarity of
solution =
\[\frac{\text{No}\text{.of}\,\text{moles}}{\text{Volume}\,\text{of}\,\text{solution}}\text{=}\frac{\text{1}}{\text{10}}\text{
}\!\!\times\!\!\text{ }\frac{\text{1}}{\text{0}\text{.2}}\]
=0.5 M
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