• # question_answer 7) A solution of $NaOH$ is prepared by dissolving 4g of it in $200c{{m}^{3}}$ of the solution. Calculate the molarity of the solution.

Answer:

Molecular mass of $NaOH=23+16+1=40$ No. of moles of $NaOH=\frac{4}{40}=\frac{1}{10}$ Volume of solution = $200c{{m}^{3}}=0.2L$ Molarity of solution = $\frac{\text{No}\text{.of}\,\text{moles}}{\text{Volume}\,\text{of}\,\text{solution}}\text{=}\frac{\text{1}}{\text{10}}\text{ }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{0}\text{.2}}$ =0.5 M

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