11th Class Chemistry Some Basic Concepts of Chemistry

  • question_answer 7) A solution of \[NaOH\] is prepared by dissolving 4g of it in \[200c{{m}^{3}}\] of the solution. Calculate the molarity of the solution.

    Answer:

    Molecular mass of \[NaOH=23+16+1=40\] No. of moles of \[NaOH=\frac{4}{40}=\frac{1}{10}\] Volume of solution = \[200c{{m}^{3}}=0.2L\] Molarity of solution = \[\frac{\text{No}\text{.of}\,\text{moles}}{\text{Volume}\,\text{of}\,\text{solution}}\text{=}\frac{\text{1}}{\text{10}}\text{ }\!\!\times\!\!\text{ }\frac{\text{1}}{\text{0}\text{.2}}\] =0.5 M


You need to login to perform this action.
You will be redirected in 3 sec spinner