• # question_answer 37) Calculate the molality of a solution of ethanol in water in which the mole fraction of ethanol is 0.04.

We know $m=\frac{{{x}_{B}}\times 1000}{(1-{{x}_{B}}){{m}_{A}}}$ (i) ${{x}_{B}}=$ Mole fraction of solute = 0.04 ${{m}_{A}}=$ Molar mass of solvent = 18 Putting these values in Eqn. (i), we get $m=\frac{0.04\times 1000}{(1-0.04)\times 18}=2.31$