question_answer 36)

Which of the following has largest number of atoms? (i) 1 g of Au (ii) 1 g of Na (iii) 1 g of K (iv) 1 g of \[C{{l}_{2}}\]  

Answer:

(i) Number of atoms = \[\frac{W}{{{A}_{w}}}\times 6.023\times {{10}^{23}}\] \[=\frac{1}{197}\times 6.023\times {{10}^{23}}\] \[=3.06\times {{10}^{21}}atoms\] (ii) Number of atoms = \[\frac{1}{23}\times 6.023\times {{10}^{23}}\] \[=2.62\times {{10}^{22}}atoms\] (iii) Number of atoms = \[\frac{1}{39}\times 6.023\times {{10}^{23}}\] (iv) Number of molecules = \[\frac{W}{{{M}_{w}}}\times 6.023\times {{10}^{23}}\] \[=\frac{1}{71}\times 6.023\times {{10}^{23}}\] Number of atoms = \[2\times \frac{1}{71}\times 6.023\times {{10}^{23}}\] \[=1.67\times {{10}^{22}}atoms\] atoms \[\therefore \] 1 g Na has maximum number of atoms.