question_answer 34)

If ten volumes of dihydrogen gas reacts with five volumes dioxygen gas, how many volumes of water vapour would be produced?

Answer:

The given reaction is: \[\begin{align} & {{H}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}{{H}_{2}}O(g) \\ & \begin{matrix} \,\,\,1\,mol\,\,\,\, & \,\,\,\,\,\,\,\frac{1}{2}mol & \,\,\,\,\,\,\,\,\,\,\,\,1\,mol \\ \end{matrix} \\ & \begin{matrix} \,\,\,1\,vol\,\,\,\, & \,\,\,\,\,\,\,\frac{1}{2}vol & \,\,\,\,\,\,\,\,\,\,\,\,1\,vol \\ \end{matrix} \\ & \begin{matrix} \,\,\,10\,vol\,\, & \,\,\,\,\,\,\,5\,vol & \,\,\,\,\,\,\,\,\,\,\,\,10\,vol \\ \end{matrix} \\ \end{align}\] Thus, 10 volumes of water vapour will be obtained.