• question_answer 30) If the speed of light is $3\times {{10}^{8}}m{{s}^{-1}}$, calculate the distance covered by light in 2.00 ns.

Distance = speed x time $=3\times {{10}^{8}}\times 2\times {{10}^{-9}}$ $=6\times {{10}^{-1}}=0.6m$