11th Class Chemistry Some Basic Concepts of Chemistry

  • question_answer 29) The following data are obtained when dinitrogen and dioxygen react together to form defferent compounds :     Mass dinitrogen Mass of dioxygen (i) 14 g 16 g (ii) 14 g 32 g (iii) 28 g 32 g (iv) 28 g 80 g.   (a) Which law of chemical combination is obeyed by the above experimental data? Given its statement, (b) Fill in the blanks in the following conversions: (i) 1 km =.. mm =..... pm (ii) 1 mg = ..... kg = ..... ng (iii) 1 mL =..... L =..... \[d{{m}^{3}}\]  

    Answer:

    (a) Ratio of masses of dioxygen that combines with fixed mass of dinitrogen are given below: Fixed mass of nitrogen = 14 g (i) (ii) (iii) (iv) 16 : 32 : 16 : 40 2 : 4 : 2 : 5 (Simple whole number ratio) Thus, law of multiple proportion is varified. (b) (i) \[1\,km=1km\times \frac{1000m}{1km}\times \frac{100cm}{1m}\times \frac{10\,mm}{1\,cm}\] \[={{10}^{6}}mm\] \[1km=1km\times \frac{1000m}{1km}\times \frac{1pm}{{{10}^{-12}}m}={{10}^{15}}pm\] (ii) \[1mg=1mg\times \frac{1g}{1000mg}\times \frac{1kg}{1000g}={{10}^{-6}}kg\] \[1mg=1mg\times \frac{1g}{1000mg}\times \frac{1ng}{{{10}^{-9}}g}={{10}^{6}}ng\] (iii) \[1mL=1mL\times \frac{1L}{1000mL}={{10}^{-3}}L\] \[1mL={{10}^{-3}}\times \frac{1d{{m}^{3}}}{1L}={{10}^{-3}}d{{m}^{3}}\]  


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