• # question_answer 19) What is the concentration of sugar $({{C}_{12}}{{H}_{22}}{{O}_{11}})$ in $mol\,{{L}^{-1}}$ if its 20 g are dissolved in enough water to make a final volume upto $2L?$

We know, $M=\frac{{{w}_{B}}\times 1000}{{{m}_{B}}\times V}$ Given : ${{w}_{B}}$ = 20 g, ${{m}_{B}}$ (molar mass of sugar) = 342 g $mo{{l}^{-1}}$ $V=2L=2000mL$ Putting these values in Eqn. (i), we get $M=\frac{20\times 1000}{342\times 2000}=0.058$