Answer:
Molecular mass of
\[N{{a}_{2}}S{{O}_{4}}=23\times 2+32+16\times 4\]
= 46 + 32 + 64
\[=142\text{
}amu\]
\[\text{
}\!\!%\!\!\text{ Sodium =}\frac{\text{Mass of Sodium}}{\text{Mass}\,\text{of}\,\text{N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}}\times
100\]
\[=\frac{46}{142}\times
100=324\]
\[\text{
}\!\!%\!\!\text{ Sulphur =}\frac{\text{ }\!\!~\!\!\text{ Mass of Sulphur
}\!\!~\!\!\text{ }}{\text{Mass}\,\text{of}\,\text{N}{{\text{a}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{
}\!\!~\!\!\text{ }}\text{ }\!\!\times\!\!\text{ 100}\]
\[=\frac{32}{142}\times
100=22.59\]
%
Oxygen \[=100-(32.4+22.5)=45\]
You need to login to perform this action.
You will be redirected in
3 sec
