Answer:
Molecular mass of glucose \[{{C}_{6}}{{H}_{12}}{{O}_{6}}\]
= (6 x atomic mass
of carbon) +
(12 x atomic
mass of hydrogen) +
(6 x atomic mass of oxygen)
\[=\left(
6\times \text{ }12.011\text{ }amu \right)+\text{ }\left( 12\times 1.008\text{
}amu \right)\text{ }+\]
\[~\left( 6\times
16\text{ }amu \right)\]
\[=\text{ }180.162\text{ }amu\]
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