Answer:
(a) \[Be{{(OH)}_{2}}\] is
amphoteric in nature. It reacts both with acids and alkalies.
\[Be{{(OH)}_{2}}+2NaOH\to
N{{a}_{2}}Be{{O}_{2}}+2{{H}_{2}}O\]
\[Be{{(OH)}_{2}}+{{H}_{2}}S{{O}_{4}}\to
BeS{{O}_{4}}+2{{H}_{2}}O\]
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