Answer:
The superoxide \[O_{2}^{-}\] is
paramagnetic because of one unpaired electron in \[{{\pi }^{*}}2p\] molecular
orbital.
\[KK\sigma
{{(2s)}^{2}}{{\sigma }^{*}}{{(2s)}^{2}}\sigma {{(2{{p}_{x}})}^{2}}\pi
{{(2{{p}_{x}})}^{2}}{{(\pi 2{{p}_{y}})}^{2}}{{\pi
}^{*}}{{(2{{p}_{x}})}^{2}}{{\pi }^{*}}{{(2{{p}_{y}})}^{1}}\]
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