Answer:
(i) \[{{H}_{2}}\]gas is evolved which
catches fire as huge amount of heat energy is released.
\[2Na+2{{H}_{2}}O\to
2NaOH+{{H}_{2}}\]
(ii) Sodium peroxide is formed. It always contains small
amounts of\[N{{a}_{2}}O\].
\[4Na+{{O}_{2}}\to
2N{{a}_{2}}O\]
\[2N{{a}_{2}}O+{{O}_{2}}\to 2N{{a}_{2}}{{O}_{2}}\]
(iii) \[{{H}_{2}}{{O}_{2}}\]is
formed.
\[N{{a}_{2}}{{O}_{2}}+2{{H}_{2}}O\to
2NaOH+{{H}_{2}}{{O}_{2}}\]
The reaction is
exothermic. \[{{H}_{2}}{{O}_{2}}\]gets decomposed.
\[2{{H}_{2}}{{O}_{2}}\to
2{{H}_{2}}O+{{O}_{2}}.\]
You need to login to perform this action.
You will be redirected in
3 sec
